The UFC flyweight division has seen some exciting developments in recent years, and one fighter who has been making waves is Muhammad Mokaev. The young fighter from the UK has been climbing the ranks and has been calling out some of the biggest names in the division.
One name that has come up in discussions is Matt Schnell, who shared his thoughts on a potential matchup with Mokaev on a Q&A over on the Against the fence channel.
In an interview, Schnell acknowledged Mokaev's skills as a fighter, describing him as a "scary young up-and-coming fella." He also mentioned that he was offered a fight with Mokaev in London on March 18th or 19th, but the timing didn't work for him.
However, Schnell seemed open to the possibility of a future matchup, saying that it would be "fun to come over to London and fight the hometown kid."
So, what can we expect from a potential matchup between Schnell and Mokaev? Let's take a closer look at both fighters.
Schnell is currently ranked #8 in the UFC flyweight division and is known for his striking and grappling skills. Schnell is coming off a loss against Matheus Nicolau, however, is still at the top of the table in the flyweight division.
On the other hand, Muhammad Mokaev is an up and coming star in the division from the UK. After beating Jafel Filho at UFC 286, he's got his sights firmly set at the top 10 of the division.
When looking at the potential matchup, it's clear that both fighters bring different skill sets to the table. Schnell is a well-rounded fighter with strong striking and grappling abilities, while Mokaev is known for his exceptional grappling and wrestling skills. The key to this matchup would likely be whether Schnell can keep the fight standing or if Mokaev can take the fight to the ground.
If the fight does go to the ground, Mokaev would have the advantage. However, if Schnell can keep the fight standing and use his striking skills, he could potentially earn a victory. It would be an interesting matchup between an experienced fighter in Schnell and a rising star in Mokaev.
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